Friday, 22 April 2016

Experiment 3 - Fast Fourier Transform

In this experiment we had to develop a program to perform FFT and IFFT of an N point signal . Here I considered N=4 
So for N=4 with x(n)={10,11,12,13 } , I obtained X[k]={46,-2+2j,-2,-2-2j} on performing FFT and vice versa for IFFT . 
So thus I learnt that the number of arithmetic calculations in FFT are very less as compared DFT . Hence FFT is a faster method . 
link for the code : https://drive.google.com/drive/folders/0BwYB93kRygZnT1E1MUNaZXh4RGM

4 comments:

  1. Number of computations required are less, thus speed increases.

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  2. It seems FFT is very much preferable over DFT.

    ReplyDelete
    Replies
    1. Do you have any doubt about efficiency of FFT?
      Can you post why FFT is faster than DFT?

      Delete
  3. FFT is faster than DFT as operations in FFT are independant.

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